> The fly in the ointment with your solution is that to align the network to
> a /27, you give it an assigned address of 0,32,64 etc. This has the
> unsavory result of giving a host address of .0 and the first host on every
> portmaster the same address as the corresponding subnet (I said unsavory,
> not impossible).
It could be argued that the portmasters are giving the equivelent of the
.0 address out already, for example x.x.x.8 is given out from the
x.x.x.8/29 subnet.
Curtis
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"There is an exception to every - Curtis Coleman, - (204) 985-9025
rule, except this one." . - Telenetworkputerologist - Pangea.CA Inc.